Saturday, February 23, 2008

More Math!!

http://tomlinhollyblog.blogspot.com/2008/02/more-math.html


Esh realized that this could be solved by using a sequence of linear equations and solving for x! Fisrt figure out where the smallest and biggest numbers must go in order to have the summations work. Solutions are posted!
A+B+C=23
H+C=11
A+F=9
H+G+F=12
etc.

Words 2

http://tomlinhollyblog.blogspot.com/2008/02/words-2.html

The repeating letter is a consonant not a vowel. The vowels in these word sets are "a", "e", and "i".

Words!!!!

http://tomlinhollyblog.blogspot.com/2008/02/words.html

Each number represents the same letter! The two sets are just rearrangments of each other.

Multiplication Puzzle

http://tomlinhollyblog.blogspot.com/2008/02/multiplication-puzzle.html

Hint 1: The A in the answer must be an even digit since Ex4 must be an even number. Therefore A must be 0, 2, 4, 6, or 8 (or Ex4 must end in 0, 2, 4, 6 or 9)

Hint 2: However A cannot be zero because the original number would then start with a zero. So A can only be 2, 4, 6 or 8

Hint 3: Since A cannot be zero, E cannot be zero because 0x4 would be 0 which would make A=0 and we can't have A=0 by Hint 1.

Friday, February 22, 2008

Another Math Puzzle

http://tomlinhollyblog.blogspot.com/2008/02/another-math-puzzle.html

First notice how many letters there are. Is every digit represented by a letter? Then think about the multiplication tables. 5 produces products ending in only 5 and 0. 1 when multiplied by any number produces that number. Two digits multiplication products out number single digit products. In other words, 2 times 3 is 6; but 2 times 5 is 10. Note that TRAF is subtracted from TRACKS only one digit is ptoduced. Does this give you any idea about any of the digits in OAT? Also notice that T times ERE produces HCH.

Feyman Puzzle Hints

http://tomlinhollyblog.blogspot.com/2008/02/feynman-math-puzzle.html

First note that on line 5, A is subtracted from A so you know the number below this must be zero. Then note that the second number in line 1 produces a three digit number when multiplied by 2 as shown by line 5. There are only two number that can do this, 2 or 3. Also not many number combnations can generate the AA combination in line 4. Finally, line 6 results from A being multiplied together with line 2.

For a complete solution go to the solutions blog, listed in the Links List over on the right. Good luck!